Submission #5877637
Source Code Expand
#include <bits/stdc++.h>
using namespace std;
#define FOR(i,a,b) for(int i=(a),i##formax=(b);i<i##formax;i++)
#define FORR(i,a,b) for(int i=(a),i##formax=(b);i>=i##formax;i--)
#define pb push_back
#define mp make_pair
#define fi first
#define se second
#define pcnt __builtin_popcount
#define sz(x) (int)(x).size()
#define maxs(x,y) x=max(x,y)
#define mins(x,y) x=min(x,y)
#define show(x) cout<<#x<<" = "<<x<<endl;
#define all(a) (a.begin()),(a.end())
#define each(it,c) for(__typeof((c).begin()) it=(c).begin();it!=(c).end();it++)
#define perm(c) sort(all(c));for(bool c##p=1;c##p;c##p=next_permutation(all(c)))
#define uniq(v) sort(all(v));v.erase(unique(all(v)), v.end());
#define bit(n) (1LL<<(n))
#define randInt(l,r) (uniform_int_distribution<ll>(l,r)(rnd))
#define randDouble(l,r) (uniform_real_distribution<double>(l,r)(rnd))
typedef long long ll;
typedef __int128_t lll;
typedef pair<int,int> pii;
typedef pair<ll,ll> pll;
template<class T>using V=vector<T>;
template<class T>using VV=V<V<T>>;
template<class T,class Y>ostream& operator<<(ostream& o,const pair<T,Y>& p){return o<<"("<<p.fi<<", "<<p.se<<")";}
template<typename A,size_t N,typename T>void Fill(A (&array)[N],const T&v){fill((T*)array,(T*)(array+N),v);}
lll gcd(lll a,lll b,lll &x,lll &y){if(!b){x=1;y=0;return a;}lll d=gcd(b,a%b,y,x);y-=a/b*x;return d;}
ll gcd(ll a,ll b){lll x=0,y=0;return gcd(a,b,x,y);}
ll modPow(lll a,lll n,ll m){if(!a)return a;lll p=1;for(;n>0;n>>=1,a=a*a%m)if(n&1)p=p*a%m;return(ll)p;}
bool isPrime(ll n){if(n<2||n%2==0)return n==2;lll t=n-1,d=t/(t&-t);for(lll a:{2,325,9375,28178,450775,9780504,1795265022})if(a%n){for(t=d,a=modPow(a,t,n);t!=n-1&&a!=1&&a!=n-1;a=a*a%n,t=t*2%n);if(a!=n-1&&t%2==0)return 0;}return 1;}
void dout(double d){printf("%.12f\n",d);}
const int IINF = 1e9+6;
const ll LINF = 1e18;
const int MOD = 1e9+7;
const double PI = acos(-1);
const double EPS = 1e-10;
static random_device rd;
static mt19937 rnd(rd());
const int N = 1e6+1;
ll DP[N];
int n, k;
main(){
cin.tie(0);
ios::sync_with_stdio(false);
cin >> n >> k;
DP[0] = 1;
ll s = 1;
FOR(i, 2, n+1){
s += DP[i-1];
if(i>k) s -= DP[i-k-1];
DP[i] = s %= MOD;
}
cout << ((s-DP[n-k])%MOD+MOD)%MOD << endl;
}
Submission Info
Submission Time |
|
Task |
F - 準急 |
User |
char134217728 |
Language |
C++14 (GCC 5.4.1) |
Score |
4 |
Code Size |
2261 Byte |
Status |
AC |
Exec Time |
9 ms |
Memory |
8064 KB |
Judge Result
Set Name |
All |
Score / Max Score |
4 / 4 |
Status |
|
Set Name |
Test Cases |
All |
00, 01, 02, 03, 04, 90, 91 |
Case Name |
Status |
Exec Time |
Memory |
00 |
AC |
9 ms |
8064 KB |
01 |
AC |
9 ms |
8064 KB |
02 |
AC |
5 ms |
4352 KB |
03 |
AC |
4 ms |
4352 KB |
04 |
AC |
9 ms |
7552 KB |
90 |
AC |
1 ms |
256 KB |
91 |
AC |
1 ms |
256 KB |