Submission #4169216


Source Code Expand

{-# LANGUAGE BangPatterns #-}
import Data.Int (Int64)
import qualified Data.Vector.Unboxed as V
import Data.List (foldl',tails)
import Data.Maybe (fromMaybe)

modulo = 1000000007 :: Int64
addMod !x !y = (x + y) `mod` modulo
mulMod !x !y = (x * y) `mod` modulo
sumMod = foldl' addMod 0

-- 多項式は
--   V.fromList [a,b,c,...,z] = a + b * X + c * X^2 + ... + z * X^(k-1)
-- により表す。

-- 多項式を X^k - X^(k-1) - ... - X - 1 で割った余りを返す。
reduce :: Int -> V.Vector Int64 -> V.Vector Int64
reduce !k !v | V.last v == 0 = V.init v
             | V.length v <= k = v
             | otherwise = let b = V.last v
                               l = V.length v
                           in reduce k (V.imap (\i a -> if i >= l - k - 1 then a `addMod` b else a) (V.init v))

-- 多項式の積を X^k - X^(k-1) - ... - X - 1 で割った余りを返す。
mulP :: Int -> V.Vector Int64 -> V.Vector Int64 -> V.Vector Int64
mulP !k !v !w = reduce k $ V.generate (V.length v + V.length w - 1) $
                \i -> sumMod [(v V.! (i-j)) `mulMod` (w V.! j) | j <- [0..V.length w-1], j <= i, j > i - V.length v]

-- 多項式に X をかけたものを X^k - X^(k-1) - ... - X - 1 で割った余りを返す。
mulByX :: Int -> V.Vector Int64 -> V.Vector Int64
mulByX !k !v
  | V.length v == k = let !v_k = v V.! (k-1)
                      in V.generate k $ \i -> if i == 0
                                              then v_k
                                              else v_k `addMod` (v V.! (i - 1))
  | otherwise = V.generate (V.length v + 1) $ \i -> if i == 0
                                                    then 0
                                                    else v V.! (i - 1)

-- X の(mod X^k - X^(k-1) - ... - X - 1 での)n 乗
powX :: Int -> Int -> V.Vector Int64
powX !k !n = doPowX n
  where
    doPowX 0 = V.fromList [1]   -- 1
    doPowX 1 = V.fromList [0,1] -- X
    doPowX i = case i `quotRem` 2 of
                 (j,0) -> let !f = doPowX j -- X^j mod P
                          in mulP k f f
                 (j,_) -> let !f = doPowX j -- X^j mod P
                          in mulByX k (mulP k f f)

main :: IO ()
main = do
  l <- getLine
  let [(k, l')] = (reads :: ReadS Int) l
      [(n, _)] = (reads :: ReadS Int) l'
  if n <= k
    then print 1
    else do
    let f = powX k (n - k) -- X^(n-k) mod X^k - X^(k-1) - ... - X - 1
    let seq = replicate k 1 ++ map (sumMod . take k) (tails seq) -- 数列
    print $ sumMod $ zipWith mulMod (V.toList f) (drop (k-1) seq)

Submission Info

Submission Time
Task T - フィボナッチ
User mod_poppo
Language Haskell (GHC 7.10.3)
Score 8
Code Size 2603 Byte
Status AC
Exec Time 1130 ms
Memory 2172 KB

Judge Result

Set Name All
Score / Max Score 8 / 8
Status
AC × 7
Set Name Test Cases
All 00, 01, 02, 03, 04, 90, 91
Case Name Status Exec Time Memory
00 AC 1130 ms 1788 KB
01 AC 611 ms 1532 KB
02 AC 1126 ms 1660 KB
03 AC 188 ms 2172 KB
04 AC 2 ms 508 KB
90 AC 2 ms 508 KB
91 AC 2 ms 508 KB