Submission #3779863

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Source Code Expand

#include <bits/stdc++.h>
using namespace std;
long long int D;
int N;
int memo[101][75][40][20]={{{{0}}}};
long int P(int i,int a,int b,int c){
    int ans=0;
    if(i == 1){
        for(int j=1;j<=6;j++){
            if(j % (int)(pow(2,a)*pow(3,b)*pow(5,c)) == 0) ans++;
        }
        return memo[1][a][b][c] = ans;
    }
    if(memo[i][a][b][c] != 0) return memo[i][a][b][c];
    ans = P(i-1,a,b,c) + P(i-1,max(a-1,0),b,c) + P(i-1,a,max(b-1,0),c) + P(i-1,max(a-2,0),b,c) + P(i-1,a,b,max(c-1,0)) + P(i-1,max(a-1,0),max(b-1,0),c);
    return memo[i][a][b][c] = ans;
}

int main(){
    cin >> N >> D;
    int a=0;
    int b=0;
    int c=0;
    while(D%2 == 0){
        D = D/2;
        a++;
    }
    while(D%3 == 0){
        D = D/3;
        b++;
    }
    while(D%5 == 0){
        D = D/5;
        c++;
    }
    if(D != 1) cout << 0 << endl;
    else cout << double(P(N,a,b,c) / powl(6,N)) << endl;
    return 0;
}

Submission Info

Judge Result