Submission #447917


Source Code Expand

#include <algorithm>
#include <array>
#include <sstream>
#include <cstdio>
#include <cstdlib>
#include <cctype>
#include <ostream>
#include<complex>
#include <cmath>
#include <iostream>
#include <stack>
#include <fstream>
#include <queue>
#include <list>
#include <map>
#include <numeric>
#include <set>
#include <sstream>
#include <bitset>
#include <iomanip>
#include <string>
#include <vector>
#include <string>
using namespace std;
#define OB (bitset<32>)
#define REP(i,a,n) for(int i=(a); i<(int)(n); i++)
#define rep(i,n) REP(i,0,n)
#define ALLOF(c) begin(), (c),end()
typedef long long ll;

#define PI 3.141592653589793
#define EPS 0.0000001
#define MOD 1000000007
int main()
{ 
    int d;
    string n;
    int dp[10001][100];
    int ans = 0;
    int sum_ketatop = 0;
    cin >> d >> n;
    fill(*dp,*dp + 10000*100,0);
    //fill(*ans,*ans + 10000*100,0);
    dp[0][0] = 1;
    rep(i,10)
    {
        dp[1][i % d] += 1;
    }
    REP(i,1,n.length())
    {
        rep(j,max(10,d))
        {
            rep(k,10)
            {
                dp[i+1][(j+k) % d] = (dp[i+1][(j+k)% d] + dp[i][j]) % MOD ;
            }
        }
    }

    rep(i,n.length()-1)
    {
        int top = n[i]-'0';  
        rep(j,top)
        {    
            ans += dp[n.length()-i-1][(2*d-sum_ketatop - j) % d];
            ans %= MOD;     
        }
        sum_ketatop += top;
        sum_ketatop %= d;
    }
    rep(i,n[n.length()-1] - '0' + 1)
    {
        if ((2*d-sum_ketatop - i ) % d ==  0)
        {
            ans++;
        }
    }
    ans -= 1;// remove a = 0;
    cout << ans << endl;
    return 0;
}

Submission Info

Submission Time
Task E - 数
User pekoong
Language C++11 (GCC 4.8.1)
Score 4
Code Size 1690 Byte
Status AC
Exec Time 130 ms
Memory 5196 KB

Judge Result

Set Name All
Score / Max Score 4 / 4
Status
AC × 5
Set Name Test Cases
All 00, 01, 02, 90, 91
Case Name Status Exec Time Memory
00 AC 46 ms 5064 KB
01 AC 98 ms 5188 KB
02 AC 130 ms 5192 KB
90 AC 45 ms 5196 KB
91 AC 44 ms 5180 KB